Question

срочно!!!
$\frac{ log_{3}(64) }{ log_{3}(2) } + \frac{ log_{5}(9) }{ log_{5}(3) }$
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Answer 1

Формула:   $\frac{log_cB}{log_cA} = log_AB$

$\frac{log_3(64)}{log_3(2)} =log_2(64) = 6\\\frac{log_5(9)}{log_5(3)}=log_3(9)=2\\ 6+2=8$

Ответ: 8

Answer 2

Формула: log. A logs (64) - log2(64) = 6 log: (2) Logs (9) log(9) = 2 logs (3) 6 + 2 = 8 Ответ: 8❤️