Question

x^2=(2x-3)^2 !!!!!!!!!!

Answer 1

Ответ:

Объяснение:

x²=4x²-12x+9

3x²-12x+9=0

x²-4x+3=0

D= 16-12=4

x1= (4+2)/2= 3

x2= (4-2)/2= 1

Answer 2

$x^2=(2x-3)^2\\\\x^2-(2x-3)^2=0\\\\\Big(x-(2x-3)\Big )\Big(x+(2x-3)\Big)=0\\\\(-x+3)(3x-3)=0\\\\a)\; \; -x+3=0\; \; \to \; \; x=3\\\\b)\; \; \; 3x-3=0\; \; \to \; \; x=1\\\\Otvet:\; \; x=3\; ,\; x=1\; .$