Question

Разложите на множители

Answer 1

Ответ:

Объяснение:

A) =а(3а+7с)

В)=а²b(5а-2b)

С)=3b(2b²- 1)

Д)=(5а+3) (b+с)

Е)= (5m+7)(1+b)

F)=(b-c)(5a-4)

Answer 2

A) $\displaystyle \tt 3ab+7ac=a(3b+7c)$

B) $\displaystyle \tt 5a^3b-2a^2b^2=a^2b(5a-2b)$

C) $\displaystyle \tt 6b^3-3b=3b(2b^2-1)$

D) $\displaystyle \tt b(5a+3)+c(5a+3)=(5a+3)(b+c)$

E) $\displaystyle \tt (5m+7)+b(5m+7)=(5m+7)(1+b)$

F) $\displaystyle \tt 5a(b-c)+4(c-b)=5a(b-c)-4(b-c)=(b-c)(5a-4)$