Question

Как решить? Помогите​

Answer 1

1)

$\displaystyle \tt x(x+10)=8x+3\\\displaystyle \tt x^2+10x=8x+3\\\displaystyle \tt x^2+10x-8x-3=0\\\displaystyle \tt x^2+2x-3=0\\\displaystyle \tt a=1, \: \: \: \: \: b=2,\: \: \: \: \: c=-3 \: \: \: \: \:$

2)

$\displaystyle \tt (x+2)^2=2x^2+4\\\displaystyle \tt x^2+4x+4=2x^2+4\\\displaystyle \tt x^2-2x^2+4x+4-4=0\\\displaystyle \tt -x^2+4x=0\\\displaystyle \tt a=-1, \: \: \: \: \: b=4, \: \: \: \: \: c=0$