Question

Решите неравенство системой lg1/2(x)<-3​

Answer 1

$\log_{1/2}x<-3\\ \\ \log_{1/2}x<\log_{1/2}8\\ \\ \displaystyle \left \{ {{x>0} \atop {x>8}} \right.~~~\Rightarrow~~~ \boxed{x>8}$