Question

Решите уравнение пж, даю 100 баллов ​

Answer 1

$1)\frac{4}{9x^{2}-1}-\frac{4}{3x+1}-\frac{4}{1-3x}=0\\\\\frac{4}{(3x-1)3x+1)}-\frac{4}{3x+1}+\frac{4}{3x-1}=0\\\\\frac{4-4(3x-1)+4(3x+1)}{(3x-1)(3x+1)}=0\\\\\frac{4-12x+4+12x+4}{(3x-1)(3x+1)}=0\\\\\frac{12}{(3x-1)(3x+1)}=0$

Ответ : x ∈ ∅

$2)\frac{4}{y+3}-\frac{5}{3-y}=\frac{1}{y-3}-1\\\\\frac{4}{y+3}+\frac{5}{y-3}-\frac{1}{y-3}+1=0\\\\\frac{4(y-3)+5(y+3)-(y+3)+(y-3)(y+3)}{(y-3)(y+3)}=0\\\\\frac{4y-12+5y+15-y-3+y^{2}-9 }{(y-3)(y+3)}=0\\\\\frac{y^{2}+8y-9 }{(y-3)(y+3)}=0\\\\\frac{(y-1)(y+9)}{(y-3)(y+3)}=0\\\\\left \{ {{(y-1)(y+9)=0} \atop {y-3\neq0;y+9\neq0}} \right. \\\\\\y_{1}=1\\\\y_{2}=-9\\\\y\neq 3;y\neq-3\\\\Otvet:\boxed{1;-9}$