Question

Срочно!!! Пожалуйста

Answer 1

$1)\; \; \frac{x+3}{5}-\frac{x^2-4}{8}\leq1\; \Big |\cdot 40\\\\8(x+3)-5(x^2-4)\leq 40\\\\8x+24-5x^2+20\leq 40\\\\5x^2-8x-4\leq 0\\\\D/4=4^2+20=36\; ,\; \; x_1=\frac{4-6}{5}=-0,4\; \; ,\; \; x_2=\frac{4+6}{5}=2\\\\5(x+0,4)(x-2)\leq 0\\\\znaki:\; \; +++[-0,4\; ]---[\; 2\; ]+++\\\\x\in [-0,4\; ;\; 2\; ]$

$2)\; \; \frac{3x^2-11}{8}<10-\frac{37-x^2}{6}\; \Big|\cdot 24\\\\3(3x^2-11)<240-4\, (37-x^2)\\\\9x^2-33<240-148+4x^2\\\\5x^2-125<0\\\\5(x^2-25)<0\\\\5(x-5)(x+5)<0\\\\znaki:\; \; +++(-5)---(5)+++\\\\x\in (-5;5)$