Question

(X-2)^2+(x-3)^2=2x^2

Answer 1

${x}^{2} - 4x + 4 + {x}^{2} - 6x + 9 = {2x}^{2} \\ {2x}^{2} - {2x}^{2} - 4x - 6x + 4 + 9 = 0 \\ - 10x + 13 = 0 \\ - 10x = - 13 \\ x = 1\frac{3}{10}$

Удачииииииииии

Answer 2

Ответ: x=1,3

Объяснение:

(x-2)^2+(x-3)^2=2x^2

(x-2)(x-2)+(x-3)(x-3)=2x^2

x^2-2x-2x+4+x^2-3x-3x+9=2x^2

x^2-4x+4+x^2-6x+9=2x^2

2x^2-10x+13=2x^2

2x^2-10x+13-2x^2=0

-10x+13=0

-10x=-13/ *(-1)

10x=13

x=13/10

x=1,3