Предмет: Математика, автор: arlankalabaev0207

помогите пожалуйста срочно, вычислить предел функции на бесконечности. номер 2

Приложения:

Аноним: Бесконечность

Simba2017: 1)-3/9=-1/3

Simba2017: 2)бесконечность. степень числителя выше степени знаменателя

Аноним: Ирина, привет!

arlankalabaev0207: можете расписать по действиям пожалуйста?

Ответы

Автор ответа: Аноним

Разделим числитель и знаменатель дроби на старший степень x

$\displaystyle \lim_{x \to \infty}\dfrac{20x^2-5x+4}{20x-5}=\lim_{x \to \infty}\dfrac{20-\dfrac{5}{x}+\dfrac{4}{x^2}}{\dfrac{20}{x}-\dfrac{5}{x^2}}=\dfrac{20-0+0}{0-0}=\infty$

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