Question

Решите неполное квадратное уравнение:
а) -1,5х(степень 2) = 0
б) х(степень 2) – 4 = 0
в) 2x(степень 2) +7 = 0
г) х(степень 2)+ 9x = 0
д) 81x(степень 2) – 64 = 0
е) 2(x(степ.2)+4) = 4(х(степ.2) + 2).
ж) (х – 2)(степ.2) – 8 = 0​
ПРОШУ СРОЧНО

Answer 1

Ответ:

$- 1.5 {x}^{2} = 0 \\ {x}^{2} = 0 \\ x = 0$

${x}^{2} - 4 = 0 \\ (x - 2)(x + 2) = 0 \\ x - 2 = 0 \\ x + 2 = 0 \\ x = 2 \\ x = - 2$

$2 {x}^{2} + 7 = 0 \\ {x}^{2} = - \frac{7}{2} \: net \: korney$

${x}^{2} + 9x = 0 \\ x(x + 9) = 0 \\ x = 0 \\ x + 9 = 0 \\ x = - 9$

$81 {x}^{2} - 64 = 0 \\ (9x - 8)(9x + 8) = 0 \\ 9x - 8 = 0 \\ 9x + 8 = 0 \\ x = \frac{8}{9} \\ x = - \frac{8}{9}$

$2( {x}^{2} + 4) = 4({x}^{2} + 2) \\ {x}^{2} + 4 = 2 {x}^{2} + 4 \\ {x}^{2} = 0 \\ x = 0$

${(x - 2)}^{2} - 8 = 0 \\ {(x - 2) }^{2} = 8 \\ x - 2 = 2 \sqrt{2} \\ x - 2 = - 2 \sqrt{2} \\ \\ x = 2 + 2 \sqrt{2} \\ x = 2 - 2 \sqrt{2}$