Question

{sinx•siny-cosx•cosy= -1
{sinx•cosy-cosx•siny=1/2
Решить систему уравнений
50 балов!!!

Answer 1

Ответ:

Объяснение:

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Answer 2

sin(x-y)=1/2

-cos(x+y)=-1

$si(x - y) = \frac{1}{2} \\ (x - y) = {( - 1)}^{k} arcsin \frac{1}{2} + \pi \: k \\ x - y = {( - 1)}^{k} \frac{\pi}{6} + \pi \: k$

$- cos(x + y) = - 1 \\ cos(x + y) = 1 \\ x + y = 2\pi \: n$

$x - y = {( - 1)}^{k} \frac{\pi}{6} + \pi \: k \\ x + y = 2\pi \: n \\ 2x = {( - 1)}^{k} \frac{\pi}{6} + \pi \: k + 2\pi \: n \\ x = {( - 1)}^{k} \frac{\pi}{12} + \frac{\pi}{2} \: k + \pi \: n \\ y = 2\pi \: n - x = \\ = 2\pi \: n - {( - 1)}^{k} \frac{\pi}{12} + \frac{\pi}{2} \: k + \pi \: n = \\ = - {( - 1)}^{k} \frac{\pi}{12} + \frac{\pi}{2} \: k + 3\pi \: n$