Question

помогите пожалуйста​

Answer 1

#1.

a) 2² - (-3)² = 4 - (9) = -5

б) $(-2\frac{1}{2} )^3 + 0,064 = (\frac{-5}{2} )^3 * (0,4)^3 = (\frac{-5 * 4}{2 * 10} )^3 = (\frac{-2}{2})^3 = (-1)^3 = -1$

в) $(-5^4) * (-\frac{2}{5})^4 = (-5 * -\frac{2}{5})^4 = (\frac{-5 * (-2)}{5})^4 = (2)^4 = 16$

#2.

а) $\frac{(x^4)^3}{x^{11}*x} = \frac{x^{12}}{x^{12}} = 1$

б) $(-0,2ab^5)^3 = -0,0016a^3b^{15}$

в) (6x)^2 * (x * x^5)^4 = 36x^2 * x^{24} = 36x^{26}

#3.

а) $-3a^8b^3 * 2ab^6 = -6a^9b^9$

б) $-98xy^3 * (\frac{1}{7} x^2)^2$ = $-98xy^3 * \frac{1}{49} x^4 = \frac{-98x^5y^3}{49} = -2x^5y^3$

в) $(-4ab^3)^3*(-a^2b)^2 = -64a^3b^9 * a^4b^2 = -64a^7b^{11}$