Question

помогите во втором в конце 108.2​

Answer 1

$1. \; \Big(23 \dfrac{1}{21} : 1 \dfrac{3}{7} - 5,5 \Big) : 3,19 - 1 \dfrac{17}{18} = 1 \dfrac{7}{18} \\\\\\ 1) \; 23 \dfrac{1}{21} : 1 \dfrac{3}{7} = \dfrac{484}{21} : \dfrac{10}{7} = \dfrac{484}{21}\cdot \dfrac{7}{10} = \dfrac{242}{3}\cdot \dfrac{1}{5} = \dfrac{242}{15} = 16 \dfrac{2}{15} \\\\ 2) \; 16 \dfrac{2}{15} - 5,5 = 16 \dfrac{2}{15} - 5 \dfrac{1}{2} = 16 \dfrac{4}{30} - 5 \dfrac{15}{30} = 15 \dfrac{34}{30} - 5 \dfrac{15}{30} = 10 \dfrac{19}{30} \\\\ 3) \; 10 \dfrac{19}{30} : 3,19 = \dfrac{319}{30} : \dfrac{319}{100} = \dfrac{319}{30}\cdot \dfrac{100}{319} = \dfrac{1}{3}\cdot \dfrac{10}{1} = \dfrac{10}{3} = 3 \dfrac{1}{3} \\\\ 4) \; 3 \dfrac{1}{3} - 1 \dfrac{17}{18} = 3 \dfrac{6}{18} - 1 \dfrac{17}{18} = 2 \dfrac{24}{18} - 1 \dfrac{17}{18}= 1 \dfrac{7}{18} \\\\\\\\\ 2. \; \Big(64 \dfrac{1}{11} : 4 \dfrac{6}{11} - 0,8 \Big) : 9,5 + 108,2 = 109,6 \\\\\\ 1) \; 64 \dfrac{1}{11} : 4 \dfrac{6}{11} = \dfrac{705}{11} : \dfrac{50}{11} = \dfrac{705}{11}\cdot \dfrac{11}{50} = \dfrac{141}{1}\cdot \frac{1}{10} = \dfrac{141}{10} = 14 \dfrac{1}{10} = 14,1 \\\\ 2) \; 14,1 - 0,8 = 13,3 \\ 3) \; 13,3 : 9,5 = 1,4 \\ 4) \; 1,4 + 108,2 = 109,6$