Предмет: Алгебра, автор: ivanpirog74321

x²+2=4x-3, помогите это решить
Поже​

Ответы

Автор ответа: nktselepov
2

x^2+2=4x-3\\x^2-4x+5=0\\D=(-4)^2-4*5=16-20=-4<0

Корней нет

Автор ответа: sebrithien
1

\displaystyle \tt x^2+2=4x-3\\\displaystyle \tt x^2-4x+2+3=0\\\displaystyle \tt x^2-4x+5=0\\\displaystyle \tt D=(-4)^2-4\cdot1\cdot5=16-20=-4

Так как D<0, то уравнение не имеет корней.

Ответ: нет корней

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