Question

Разложить на множетели
x3-x2y-x+y

Answer 1

$x^3-x^2y-x+y=x^2(x-y)-(x-y)=(x-y)(x^2-1)=\\\\=(x-y)(x-1)(x+1)$

Answer 2

$\displaystyle \tt x^3-x^2y-x+y=x^2(x-y)-(x-y)=(x-y)(x^2-1)=\bold{(x-y)(x-1)(x+1)}$

Ответ: $\displaystyle \tt (x-y)(x-1)(x+1)$