Question

Помогите пожалуйста

Answer 1

Ответ:

$\displaystyle \tt \frac{\boxed{\displaystyle \tt 10}\:d-\boxed{\displaystyle \tt 42}}{\boxed{\displaystyle \tt d}\:(d-\boxed{\displaystyle \tt 14d})}$

Объяснение:

$\displaystyle \tt \frac{7}{d-14}+\frac{3}{d}=\frac{7d+3(d-14)}{d(d-14)}=\frac{7d+3d-42}{d(d-14)}=\bold{\frac{10d-42}{d(d-14)}}$