Question

пж пж пж номер 35.15​

Answer 1

1)

$\displaystyle \tt (5z^2-6k)^2-(5z^2+3k)^2+90z^2k=27k^2\\\displaystyle \tt 25z^4-60kz^2+36k^2-(25z^4+30kz^2+9k^2)+90kz^2=27k^2\\\displaystyle \tt 25z^4-60kz^2+36k^2-25z^4-30kz^2-9k^2+90kz^2=27k^2\\\displaystyle \tt \bold{27k^2=27k^2}$

2)

$\displaystyle \tt (m^2-n^2)(m^2+n^2)-m^2(m^2-n^2)-m^2n^2=-n^4\\\displaystyle \tt m^4-n^4-m^4+m^2n^2-m^2n^2=-n^4\\\displaystyle \tt \bold{-n^4=-n^4}$

3)

$\displaystyle \tt (1,2x^4-7y^2)(1,2x^4+7y^2)+0,56x^8+49y^4=2x^8\\\\ 1,2^2\cdot x^8-49y^4+0,56x^8+49y^4=2x^8\\\\ (\frac{6}{5})^2\cdot x^8+\frac{14}{25}x^8=2x^8\\\\ \frac{36}{25}x^8+\frac{14}{25}x^8=2x^8\\\\ \bold{2x^8=2x^8}$

4)

$\displaystyle \tt (1,4a^3-5b^2)(1,4a^3+5b^2)-2,96a^6+25b^4=-a^6\\\\ \displaystyle \tt 1,4^2\cdot a^6-25b^4-2,96a^6+25b^4=-a^6\\\\ \displaystyle \tt (\frac{7}{5})^2\cdot a^6-\frac{74}{25}a^6=-a^6\\\\ \displaystyle \tt \frac{49}{25}a^6-\frac{74}{25}a^6=-a^6\\\\ \displaystyle \tt \bold{-a^6=-a^6}$