Question

Помогите решить пожалуйста х:3=5:(х-1)
2:(х-2)=(х+2):6

Answer 1

$\frac{x}{3} = \frac{5}{x - 1} \\ x(x - 1) = 15 \\ x {}^{2} - x - 15 = 0 \\ d = \sqrt{61} \\ x1 = \frac{1 + \sqrt{61} }{2} \\ x2 = \frac{1 - \sqrt{61} }{2} \\ \\ \frac{2}{x - 2} = \frac{x + 2}{6} \\ 12 = (x - 2)(x + 2) \\ 12 = x^{2} - 4 \\ x {}^{2} = 16 \\ x1 = 4 \\ x2 = - 4$