Предмет: Математика, автор: marrygulshana

sin=1\2; 0<а<90 Найти cos a

Ответы

Автор ответа: Kudesnik212

Ответ: сos A= $\sqrt{3}$ /2

Пошаговое объяснение:

1)Sin=1/2-sin30°

значит <a=30°

2)cos30°(a)= $\sqrt{3}$ /2

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sin=1\2; 0<а<90 Найти cos a​

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sin=1\2; 0<а<90 Найти cos a