Question

Решите уравнение:
1. $x^{5}=-32$
2.$4x^{3} = 108$
3.$(5 + x)^{2} = 16$

Answer 1

$x^{5}=-32 \\ x = \sqrt[5]{ - 32} \\ x = - 2$

$4x^{3} = 108 \: \: \: \: | \div 4\\x {}^{3} = 27 \\ x = \sqrt[3]{27} \\ x = 3$

$(5 + x)^{2} = 16 \: \: | \sqrt{} \\ | 5 + x | = 4 \\ 1. \: \: \: \: 5 + x = 4 \\ x = - 1 \\ 2. \: \: \: \: \: 5 + x = - 4 \\ x = - 9$