Question

Помогите пожалуйста решить алгебру быстрее

Answer 1

$1)\frac{x^{2}-3x-4 }{x+1}=0\\\\\left \{ {{x^{2}-3x-4=0 } \atop {x+1\neq0 }} \right.\\\\\left \{ {{x_{1}=4;x_{2}=-1} \atop {x\neq-1 }} \right.\\\\Otvet:\boxed{4}$

$2)\frac{3x^{2}-7x }{x-3}=\frac{2x^{2}-6 }{3-x}\\\\\frac{3x^{2}-7x }{x-3}-\frac{2x^{2}-6 }{3-x}=0\\\\\frac{3x^{2}-7x }{x-3}+\frac{2x^{2}-6}{x-3} =0\\\\\frac{3x^{2}-7x+2x^{2}-6}{x-3}=0\\\\\frac{5x^{2} -7x-6}{x-3}=0\\\\x-3\neq0\Rightarrow x\neq3\\\\5x^{2}-7x-6=0\\\\D=(-7)^{2}-4*5*(-6)=49+120=169=13^{2}\\\\x_{1}=\frac{7-13}{10}=-0,6\\\\x_{2}=\frac{7+13}{10}=2\\\\Otvet:\boxed{-0,6;2}$