Question

СРОЧНО НУЖЕН РЕШЕНИЕ!!!!

Answer 1

$\frac{ \sqrt{xy} + x}{ \sqrt{xy} + y } = \frac{( \sqrt{xy} + x)( \sqrt{xy} - y)}{( \sqrt{xy} + y) \sqrt{xy} - y) } = \frac{xy - y \sqrt{xy} + x \sqrt{xy} - xy }{xy - {y}^{2} } = \\ = \frac{ \sqrt{xy}(x - y) }{y(x - y)} = \frac{ \sqrt{xy} }{y}$

Answer 2

$\dfrac{\sqrt{xy}+x}{\sqrt{xy}+y}=\dfrac{\sqrt{x}\cdot (\sqrt{y}+\sqrt{x})}{\sqrt{y}\cdot (\sqrt{x}+\sqrt{y})}=\dfrac{\sqrt{x}}{\sqrt{y}}=\dfrac{\sqrt{x}\cdot \sqrt{y}}{\sqrt{y}\cdot \sqrt{y}}=\dfrac{\sqrt{xy}}{y}$