Question

32^x-1=(1:16)^2x-1помогите решить 

Answer 1

$32^{x-1}=(frac{1}{16})^{2x-1}\ (2^5)^{x-1}=(2^{-4})^{2x-1}\ 2^{5x-5}=2^{4-8x}\ 5x-5=4-8x\ 5x+8x=4+5\ 13x=9\ x=frac{9}{13}$