Question

Помогите пожалуйста решить номер 461(2,4) 462(2,4,6) 463(2,4) 464(2,4,6)

Answer 1

461 (2,4)

$\frac{-64}{-80} =\frac{64}{80} =\frac{16*4}{16*5} =\frac{4}{5} =0,8\\ \\ \frac{28}{-14} =-\frac{14*2}{14} =-2$

462 (2,4,6)

$\frac{2c}{3c} =\frac{2}{3} \\ \\ \frac{4ab}{8ac} =\frac{b}{2c} =0.5bc\\ \\ \frac{5x}{x^{3} y} =\frac{5}{x^{2} y}$

463 (2.4)

$\frac{b^{3} }{b^{7} }= \frac{b^{3} }{b^{3+4} }=\frac{b^{3} }{b^{3}*b^{4} }=\frac{1}{b^{4} } \\ \\ \frac{b^{6} }{b^{4} }=b^{6} :b^{4}=b^{6-4} =b^{2}$

464 (42.4.6)

$\frac{14c}{49c} =\frac{7c*2}{7c*7} =\frac{2}{7}\\ \\ \frac{3a^{2} b}{9a^{3} } =\frac{3a^{2} b}{3*3a^{2}a } =\frac{b}{3a} \\ \\ \frac{25a^{3} bc^{2} }{125ac^{3} } =\frac{25a^{2} abc^{2} }{3*25ac^{2}c }=\frac{a^{2}b }{3c}$