Question

Помогите решить❗❗❗❗❗❗​

Answer 1

Ответ:

Пошаговое объяснение:

1.

а) y' = 6*4x³ - 9eˣ = 24x³ - 9eˣ

b) $y' = \dfrac{1}{2\sqrt{x+5} }$

v) $y' = e^{x^2} + x*2x*e^{x^2}$

g) $y' = \dfrac{3x^2(x^2-1)-2x(x^3+1)}{(x^2-1)^2}=\dfrac{x^4-3x^2-2x}{(x^2-1)^2}$

d) $y' = \dfrac{1}{xln5}$

e)$y' = \dfrac{2}{cos^22x}$

2.

f'(x) = 12x³ - 12x² - 24x = 0

x(x² - x - 2) = 0

x1 = 0

x2 = -1

x3 = 2

3.

tgα = f'(x0)

f'(x) = 1/√x

f'(x0) = 1/√3 = tgα

α = 30°