Question

Разложите на множители x^3y^2-x^3-xy^2+x

Answer 1

$\displaystyle \tt x^3y^2-x^3-xy^2+x=x(x^2y^2-x^2-y^2+1)=x(x^2(y^2-1)-(y^2-1))=x(x^2(y-1)(y+1)-(y-1)(y+1))=x(y-1)(y+1)(x^2-1)=\boxed{\bold{x(y-1)(y+1)(x-1)(x+1)}}$