Question

Решите пожалуйста . С объяснениями пожайлуста.
Решите системы неравенств
№969
3,4,5,6

Answer 1

Ответ:

вообщем, вот..

Пошаговое объяснение:

на фото

Answer 2

Решение:

$969.3.\\\\ \left \{ {{4x+9>-15} \atop {2-x\leq5}} \right. \\\\ \left \{ {{4x>-15-9} \atop {-x\leq5-2}} \right. \\\\ \left \{ {{4x>-24} \atop {-x\leq3}} \right. \\\\ \left \{ {{x>-6} \atop {x\geq-3}} \right.\\\\ x\in [-3; \infty)$

$969.4.\\\\\left \{ {{2x+3 \geq x-1} \atop {5x-22 \leq x+2}} \right. \\\\\left \{ {{2x-x \geq -1-3} \atop {5x-x \leq 2+22}} \right. \\\\\left \{ {{x \geq -4} \atop {4x \leq 24}} \right. \\\\\left \{ {{x \geq -4} \atop {x \leq 6}} \right. \\\\x\in [-4; 6]$

$969.5.\\\\\left \{ {{7x + 9 < 2x - 1} \atop {4+11x>9x-14}} \right. \\\\\left \{ {{7x - 2x < -1 - 9} \atop {11x-9x>-14-4}} \right.\\\\\left \{ {{5x<-10} \atop {2x>-18}} \right. \\\\\left \{ {{x<-2} \atop {x>-9}} \right.\\\\x \in (-9; -2)$

$969.6\\\\\left \{ {{x\geq0} \atop {x-5>2x+1}} \right. \\\\\left \{ {{x\geq0} \atop {x-2x> 1 + 5}} \right. \\\\\left \{ {{x\geq0} \atop {-x>6}} \right. \\\\\left \{ {{x\geq0} \atop {x<-6}} \right. \\\\x\in (-\infty; -6) \cup [0; \infty)$