Question

Ребята помогите пожалуйста ​

Answer 1

Ответ:

Объяснение:

1)  =(x+y)(x+y)=(x+y)²

2) =(c-6)(c-6)=(c-6)²

3) =(a+2)(a+2)=(a+2)²

4) =(4x-3y)(4x-3y)=(4x-3y)²

5) =(m-3)(m-3)=(m-3)²

6)  =(1+7k)(1+7k)=(1+7k)²

7) =(3c-8)(3c-8)=(3c-8)²

8) =(5a+2b)(5a+2b)=(5a+2b)²

9) =(y-1)(y-1)=(y-1)²

10) =(a+5)(a+5)=(a+5)²

11) =(5n+7)(5n+7)=(5n+7)²

12) =(b-2a)(b-2a)=(b-2a)²

13) =(0,5x-2y)(0,5x-2y)=(0,5x-2y)²

14) =(m-0,5)(m-0,5)=(m-0,5)²

Answer 2

$\displaystyle \tt 1)\: x^2+2xy+y^2=(x+y)^2=(x+y)(x+y)\\\displaystyle \tt 2)\: c^2-12c+36=(c-6)^2=(c-6)(c-6)\\\displaystyle \tt 3)\: a^2+4a+4=(a+2)^2=(a+2)(a+2)\\\displaystyle \tt 4)\: 16x^2-24xy+9y^2=(4x-3y)^2=(4x-3y)(4x-3y)\\\displaystyle \tt 5)\: m^2-6m+9=(m-3)^2=(m-3)(m-3)\\\displaystyle \tt 6)\: 1+13k+49k^2=(1+7k)^2=(1+7k)(1+7k)\\\displaystyle \tt 7)\: 64+9c^2-48c=(8-3c)^2=(8-3c)(8-3c)$

$\displaystyle \tt 8)\: 20ab+25a^2+4b^2=(5a+2b)^2=(5a+2b)(5a+2b)\\\displaystyle \tt 9)\: 1+y^2-2y=(1-y)^2=(1-y)(1-y)\\\displaystyle \tt 10)\: -a^2-10a-25=-(a+5)^2=-(a+5)(a+5)\\\displaystyle \tt 11)\: 25n^2+49+70n=(5n+7)^2=(5n+7)(5n+7)\\\displaystyle \tt 12)\: -b^2-4a^2+4ab=-(b-2a)^2=-(b-2a)(b-2a)\\\displaystyle \tt 13)\: \frac{1}{4}x^2-2xy+4y^2=(\frac{1}{2}x-2y)^2=(\frac{1}{2}x-2y)(\frac{1}{2}x-2y)\\\displaystyle \tt 14)\: m^2-m+0,25=0,25(2m-1)^2=0,25(2m-1)(2m-1)$