Question

помогите решить неравенство

$\frac{2x-1}{3} - \frac{4x+2}{5} \leq 0$

Answer 1

$\displaystyle \tt \frac{2x-1}{3}-\frac{4x+2}{5}\leq 0 \: \: \: \: \: | \cdot 15\\\displaystyle \tt 5(2x-1)-3(4x+2)\leq 0\\\displaystyle \tt 10x-5-12x-6\leq 0\\\displaystyle \tt -2x-11\leq 0\\\displaystyle \tt -2x\leq 11\\\displaystyle \tt x\geq -\frac{11}{2}\\x\geq -5,5\\\\\displaystyle \tt \underline{\bold{x\in[-5,5;\:+\infty)}}$