Question

помогите пожалуйста с тригонометрией

Answer 1

Ответ: -√3/3;  -5/12 π;   -1;    18°;   -1.

Объяснение:

1) ctg(-7π/3) = ctg(2π-π/3) = -ctg π/3 =  -√3 / 3.

2) arccos 1/2 + arctg 1 - 3 arcctg √3 + arcsin (-1/2) =

= π/3 + π/4 - 3*π/6 + (-π/6) = π/3-π/4-π/2 =

= 4π/12-3π/12-6π/12 = -5π/12 = -5/12 π.

3) 2sin(arccos(-√3/2) ) = 2sin(-π/6) = -2sin π/6 = -2* 1/2 = -1.

   arcsin(cos0) : 5= arcsin 1 : 5= π/2 : 5 = π/10 = 18°.

4) cosπ+sin(-2π)-cos(-π/2) = -1+0-0 = -1.