Question

$x+\frac{3x-9}{5} =11-\frac{15x-12}{3}$ Пожалуйста с объяснением

Answer 1

$\displaystyle \tt x+\frac{3x-9}{5}=11-\frac{15x-12}{3}\: \: \: \: | \cdot15\\\displaystyle \tt 15x+3(3x-9)=165-5(15x-12)\\\displaystyle \tt 15x+9x-27=165-75x+60\\\displaystyle \tt 24x-27=225-75x\\\displaystyle \tt 24x+75x=225+27\\\displaystyle \tt 99x=252\\\displaystyle \tt x=\frac{252}{99}\\\displaystyle \tt x=\frac{28}{11}\\\displaystyle \tt x=2\frac{6}{11}$

Answer 2

Ответ:

$\boxed{\bold{x = \frac{28}{11} }}$

Объяснение:

$x + \frac{3x-9}{5} = 11 - \frac{15x-12}{3}$

$\frac{8x-9}{5} =11-\frac{15x-12}{3}$

$\frac{8x-9}{5} =-5x+15$

$8x - 9 = -5x * 5 + 15 * (5)$

$8x-9=-25x+75$

$33x - 9 = 75$

$33x = 84$

$x = \frac{28}{11}$

Ответ: $\boxed{\bold{x = \frac{28}{11} }}$