Question

64х^3-16x^2 + x = 0​

Answer 1

Ответ:

1/8; 0

Объяснение:

$64 {x}^{3} - 16 {x}^{2} + x = 0 \\ x(64 {x}^{2} - 16x + 1) = 0 \\ x(8x - 1) {}^{2} = 0 \\ x = 0 \\ 8x - 1 = 0 \\ x = \frac{1}{8}$

Answer 2

$\displaystyle \tt 64x^3-16x^2+x=0\\\displaystyle \tt x(64x^2-16x+1)=0\\\displaystyle \tt x(8x-1)^2=0\\\displaystyle \tt x_1=0\\\displaystyle \tt 8x-1=0\\\displaystyle \tt 8x=1\\\displaystyle \tt x=\frac{1}{8}\\\displaystyle \tt x_2=0,125$