Question

Помогите Алгебра 9 класс​

Answer 1

$3(x^{2} +4)-\frac{6}{x^{2} +4}=17\\\\x^{2}+4=m,m>0\\\\3m-\frac{6}{m}-17=0\\\\\frac{3m^{2}-17m-6 }{m}=0\\\\\left \{ {{3m^{2}-17m-6=0 } \atop {m\neq 0}} \right.\\\\3m^{2}-17m-6=0\\\\D=(-17)^{2}-4*3*(-6)=289+72=361=19^{2}\\\\m_{1}=\frac{17+19}{6}=6\\\\m_{2}=\frac{17-19}{6}=-\frac{1}{3}<0-neyd\\\\x^{2}+4=6\\\\x^{2}=2\\\\x_{1} =-\sqrt{2}\\\\x_{2} =\sqrt{2}\\\\Otvet:\boxed{-\sqrt{2},\sqrt{2}}$

$- \sqrt{2} *\sqrt{2}=-(\sqrt{2})^{2}=-2\\\\Otvet:\boxed{-2}$