Question

П_жжжжж_жжжжжжжжжжжжжжжжжж​

Answer 1

$\displaystyle \tt \frac{4}{40}+y+\frac{16}{40}=\frac{31}{40}+\frac{6}{40}\\\displaystyle \tt y+\frac{20}{40}=\frac{37}{40}\\\displaystyle \tt y=\frac{37}{40}-\frac{20}{40}\\\displaystyle \tt y=\frac{17}{40}$