Question

Помогите плиз срочно нужен ​

Answer 1

$\left \{ {{\frac{1}{y}- \frac{1}{x}=\frac{1}{3}} \atop {x-2y=2}} \right.=>\left \{ {{\frac{x-y}{xy}=\frac{1}{3}} \atop {x=2y+2}} \right.=>\left \{ {{3(x-y)=xy} \atop {x=2y+2}} \right.=>\left \{ {{3(2y+2-y)}=(2y+2)y \atop {x=2y+2}} \right.=>\\\\\\=>\left \{ {{3(y+2)=2y^2+2y} \atop {x=2y+2}} \right.=>\left \{ {{3y+6=2y^2+2y} \atop {x=2y+2}} \right.=>\left \{ {{2y^2-y-6=0} \atop {x=2y+2}} \right.\\\\2y^2-y-6=0\\D=(-1)^2-4*2*(-6)=1+48=49=7^2\\y_1=(1+7)/(2*2)=8/4=2\\y_2=(1-7)/(2*2)=-6/4=-1,5$

$x_1=2y_1+2=2*2+2=4+2=6\\x_2=2y_2+2=2(-1,5)+2=-3+2=-1$

Ответ: (6; 2), (-1; -1,5)