Question

Помогите решить уравнение

Answer 1

$\sqrt{2}-1=\frac{1}{\sqrt{2}+1 } \Rightarrow\\\\(\frac{1}{\sqrt{2}+1} )^{x}+(\sqrt{2}+1)^{x} -2=0\\\\(\sqrt{2}+1)^{x}=m\\\\\frac{1}{m} +m-2=0\\\\\frac{m^{2}-2m+1}{m}=0\\\\\left \{ {{m^{2}-2m+1=0 } \atop {m\neq0 }} \right. \\\\m^{2}-2m+1=0\\\\(m-1)^{2}=0\\\\m=1\\\\(\sqrt{2}+1)^{x}=1\\\\(\sqrt{2}+1)^{x} =(\sqrt{2}+1)^{0}\\\\x=0\\\\Otvet:\boxed{0}$

Answer 2

Ответ:

Объяснение:

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