Question

Освободиться от иррациональности в знаменателе дроби

Answer 1

$\frac{22}{\sqrt{13}-\sqrt{2}}=\frac{22}{\sqrt{13}-\sqrt{2}}\cdot \frac{\sqrt{13}+\sqrt{2}}{\sqrt{13}+\sqrt{2}}=\frac{22(\sqrt{13}+\sqrt{2})}{(\sqrt{13}-\sqrt{2})(\sqrt{13}+\sqrt{2})}=\frac{22(\sqrt{13}+\sqrt{2})}{11}=2(\sqrt{13}+\sqrt{2})=2\sqrt{13}+2\sqrt{2}$