Question

29 БАЛЛОВ!!!!!!!!!
2 и 3 задание

Answer 1

Ответ:

$2)\frac{2}{3} x - \frac{1}{3} {x}^{2} = \frac{6}{5} + \frac{1}{3} {x }^{2} \\ \\ \frac{2}{3} {x}^{2} - \frac{2}{3} x + \frac{6}{5} = 0 \\10 {x}^{2} - 10x + 18 = 0 \\ \\5 {x}^{2} - 5x + 9= 0$

$3){ (\sqrt{5}x )^{2} - 2 \times \sqrt{5} x \times \frac{1}{2 \sqrt{5} } + {( \frac{1}{2 \sqrt{5} } )}^{2} } - {( \frac{1}{2 \sqrt{5} } )}^{2} + 1 \\ \\ = ( \sqrt{5} x - \frac{1}{2 \sqrt{5} } )^{2} - \frac{1}{4 \times 5} + 1 = \\ = ( \sqrt{5} x - \frac{1}{2 \sqrt{5} } )^{2} + \frac{19}{20}$