Question

$(x-2)^{2}=(x+3)(x-4)$

Answer 1

$(x-2)^2=(x+3)(x-4)\\x^2-2\cdot x\cdot 2+4=x^2-4x+3x-12\\x^2-4x+4=x^2-x-12\\x^2-x^2-4x+x=-12-4\\-3x=-16\\x=\frac{-16}{-3}\\x=5\frac{1}{3}$