Question

разложите на множители 2 14/25 x4y4 - 1 17/64 a6b8 . Пожалуйста!!

Answer 1

$2\frac{14}{25}x^4y^4-1\frac{17}{64}a^6b^8=\frac{64}{25}x^4y^4-\frac{81}{64}a^8b^8=\frac{1}{1600}(4096x^4y^4-2025a^8b^8)=\frac{1}{1600}(64x^2y^2-45a^4b^4)(64x^2y^2+45a^4b^4)$