Question

Разложите на множители:
а)
${4x}^{2}$
- 9 в)
$4a {}^{2}$
+12ab +
${9b}^{2}$

б)
$16a {}^{4}$
— 81 г)
${36x}^{2}$
– 12xy +
${y}^{2}$

Решите уравнение:
${(3x - 1)}^{2}$
+
${(4x + 2)}^{2}$
= (5х –1)
$\times$
(5х +1)​

Answer 1

4x²-9= (2x-3)(2x+3)

4a²+12ab+9b²= (2a+3b)²= (2a+3b)(2a+3b)

16a⁴-81= (4a²-9)(4a²+9)= (2a-3)(2a+3)(4a²+9)

36x²-12xy+y²= (6x-y)²= (6x-y)(6x-y)

(3x-1)²+(4x+2)²= (5x-1)(5x+1)

9x²-6x+1+16x²+16x+4-25x²+1=0

10x+6=0

5x+3=0

x= -0,6