Question

tg (вквадрате) 6x-3=o

Answer 1

Ответ:

$\tan {}^{2} (6x - 3) = 0 \\ \tan(6x - 3) = 0 \\ 6x - 3 = \arctan(0) + \pi \times n \\6x = 3 + \pi \times n \\ x = \frac{1}{2} + \frac{\pi \times n}{6}$

n є Z(целым числам)