Question

Помогите, срочно!!! Даю 60 баллов!!

Answer 1

$1)\; \; 4sin(-1280)-\sqrt3cos(-1230)+\frac{\sqrt3}{3} tg(-600)-ctg(-1395)=\\\\=-4sin(200)-\sqrt3cos(150)-\frac{\sqrt3}{3}tg(240)+ctg(-45)=\\\\=-4sin(180+20)-\sqrt3cos(180-30)-\frac{\sqrt3}{3}tg(180+60)-ctg45=\\\\=4sin20 +\sqrt3cos30+\frac{\sqrt3}{3}tg60-1=\\\\=4sin20+\sqrt3\cdot \frac{\sqrt3}{2}+\frac{\sqrt3}{3}\cdot \sqrt3-1=\\\\=4sin20+\frac{3}{2}+1-1=4sin20+1,5$

$2)\; \; 2sin(-930)-\sqrt2cos(-1755)-\sqrt3tg(-900)+\sqrt3ctg(-2310)=\\\\=-2sin(210)-\sqrt2cos(-45)+\sqrt3tg(180)-\sqrt3ctg(150)=\\\\=-2sin(180+30)-\sqrt2\cdot \frac{\sqrt2}{2}+\sqrt3\cdot 0-\sqrt3ctg(180-30)=\\\\=2sin30-1+\sqrt3ctg30=2\cdot \frac{1}{2}-1+\sqrt3\cdot \sqrt3=3$