Question

Решите пж алгебра 8 класс

Answer 1

Ответ:

$a)4\sqrt{6}-\sqrt{24}+\sqrt{54}=4\sqrt{6}-2\sqrt{6}+3\sqrt{6}=5\sqrt{6}\\b)(\sqrt{54}-\sqrt{24})*\sqrt{6}=(3\sqrt{6}-2\sqrt{6})*\sqrt{6}=\sqrt{6}\sqrt{6}=6\\c)(4\sqrt3}+5)^2=16*3+40\sqrt{3}+25=73+40\sqrt{3}\\d)(3\sqrt{2}+2\sqrt{5})(3\sqrt{2}-2\sqrt{5})=9*2-4*5=-2\\4)a)2\sqrt{7}=\sqrt{28}\\11\sqrt{2}=\sqrt{121*2}=\sqrt{242}\\2\sqrt{7}<11\sqrt{2}\\b)2\sqrt{\frac{15}{8}}=\sqrt{\frac{4*15}{8}}=\sqrt{\frac{15}{2}}=\sqrt{7,5} \\ \frac{1}{3}\sqrt{63}=\sqrt{\frac{63}{9}}=\sqrt{7}$$2\sqrt{\frac{15}{8}} >\frac{1}{3}\sqrt{63}$

Объяснение: