Question

Помогите решить уравнение

Answer 1

$log_{ \frac{1}{ \sqrt{2} } }(2 + 2x) = - 4 \\ log_{ \frac{ \sqrt{2} }{2} }(2 + 2x) = - 4 \\ 2 + 2x = {( \frac{ \sqrt{2} }{2}) }^ {-4} \\ 2 + 2x = {( \frac{2}{ \sqrt{2} } )}^{4} \\ 2 + 2x = { \sqrt{2} }^{4} \\ 2 + 2x = {2}^{2} \\ 2 + 2x = 4 \\ 2x = 4 - 2 \\ 2x = 2 \\ x =1$

Answer 2

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