Question

Вычислите интеграл 2∫1 16dx / x^3

Answer 1

$\int\limits {16x^{-3} } \, dx = 16*\frac{x^{-3+1} }{-3+1} = 16*\frac{x^{-2} }{-2} = \frac{-8}{x^2} \\ \\ \frac{-8}{2^2} - (\frac{-8}{1^2} ) = -2+8 = 6$