Question

Просто разложить на множитили​

Answer 1

$\sqrt2-2=\sqrt2\, (1-\sqrt2)\\\\\sqrt{10}-\sqrt6=\sqrt{2}\, (\sqrt5-\sqrt3)\\\\a-2\sqrt{a}=\sqrt{a}\, (\sqrt{a}-2)\\\\a^2-3=(\sqrt{a}-\sqrt3)(\sqrt{a}+\sqrt3)\\\\m-100=(\sqrt{m}-10)(\sqrt{m}+10)\\\\1-2\sqrt{p}+p=(1-\sqrt{p})^2\\\\c+2\sqrt{cd}+d=(\sqrt{c}+\sqrt{d})^2$