Question

!!!!!решите неравенство​

Answer 1

Ответ: X€(-p/2+pn;p/4+pn)

Объяснение:

sin(2x-p/4)<корень из двух/2

2x-p/4€(-5p/4+2pn;p/4+2pn)

2x€(-p+2pn;p/2+2pn)

X€(-p/2+pn;p/4+pn)

Answer 2

$sin(\frac{\pi}{4}-2x)>-\frac{\sqrt2}{2}\\\\-\frac{\pi}{4}+2\pi k<\frac{\pi}{4}-2x<\frac{5\pi}{4}+2\pi k\; ,\; k\in Z\\\\-\frac{\pi}{2}+2\pi k<-2x<\pi +2\pi k\; ,\; k\in Z\; \; |:(-2)\\\\-\frac{\pi}{2}-\pi k<x<\frac{\pi}{4}-\pi k\; ,\; k\in Z\\\\-\frac{\pi}{2}+\pi n<x<\frac{\pi}{4}+\pi n\; ,\; n\in Z\\\\Otvet:\; \; \; \boxed {\; x\in (-\frac{\pi}{2}+\pi n\; ;\; \frac{\pi}{4}+\pi n)\; ,\; n\in Z\; }$