Question

ребят помогите пожалуйста, алгебра​

Answer 1

$1) \: {(x - 7)}^{2} - 49 = 0 \\ {x}^{2} - 14x + 49 - 49 = 0 \\ {x }^{2} - 14x = 0 \\ x(x - 14) = 0 \\ x_1 = 0 \\ x - 14 = 0 \\ x_2 = 14$

$3) \: 100 - {(z - 19)}^{2} = 0\\ 100 - ( {z}^{2} - 38z + 361) = 0 \\ 100 - {z}^{2} + 38z - 361 = 0 \\ - {z}^{2} + 38z - 261 = 0 \: \: \: \: | \times ( - 1) \\ {z}^{2} - 38z + 261 = 0 \\ {z}^{2} - 9z - 29z + 261 = 0 \\ z(z - 9) - 29(z - 9) = 0 \\ (z - 9)(z - 29) = 0 \\ z - 9 = 0 \\ z_1 = 9 \\ z - 29 = 0 \\ z_2 = 29$

Answer 2

Ответ:

(x-7)²-49=0

(x-7-7)(x-7+7)

x(x-14)=0

x=0 или x=14

Ответ: 0, 14.

100-(z-19)²=0

10²-(z-19)²=0

{10-(z-19)}{10+(z-19)}=0

(29-z)(z-9)=0

29-z=0 или z-9=0

z¹=29 z²=9

Ответ: 29, 9