Question

6pg-18p/(g-3)^2 сократите дробь

Answer 1

Ответ:

Объяснение:

$\displaystyle \[\frac{{6pg-18p}}{{{{(g-3)}^2}}}=\frac{{6p(g-3)}}{{{{(g-3)}^2}}}=\boxed{\frac{{6p}}{{g-3}}}\]$